Sash Sinha
2020-11-28 08:17:04
你可以将为每个键提供的信息元组（即和）进行比较year，month并将date其与来自的可用信息的相同子集进行比较today：
>>> import datetime
>>>
>>> def bad_food():
... today = datetime.datetime.now()
... past_due = {
... datetime.datetime(2020, 11, 24): ['chicken', 'soup', 'chips'],
... datetime.datetime(2020, 11, 27): ['lays', 'chilli'],
... }
... for key in past_due:
... if (key.year, key.month, key.day) == (today.year, today.month, today.day):
... print(past_due[key])
...
>>> bad_food()
['lays', 'chilli']
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太好了，谢谢您的帮助